2020-04
21

字典真牛

By xrspook @ 12:03:27 归类于: 扮IT

字典用好了以后666得不知道该如何形容。创造字典,搜索词典,快得就像眨眼间。列表需要考虑的长度问题,字典里一个in就高效快捷了。

这是一道扯淡的习题,因为条件没固定,参考答案可以怎么参考呢?

Exercise 5: Two words are “rotate pairs” if you can rotate one of them and get the other (see rotate_word in Exercise 5). Write a program that reads a wordlist and finds all the rotate pairs. Solution: http://thinkpython2.com/code/rotate_pairs.py.

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def rotate_word(something, n): # a-z: 97-122, A-Z: 65-90
    newletter1 = ''
    for letter in something:
        if ord(letter) < ord('A') or ord('Z') < ord(letter) < ord('a') or ord('z') < ord(letter):
            newletter2 = newletter1 + letter
        else:
            if ord(letter) + n > ord('z'):
                newletter2 = newletter1 + chr(ord(letter) + n - 26)
            elif ord('a') > ord(letter) + n > ord('Z'):
                newletter2 = newletter1 + chr(ord(letter) + n - 26)
            else:
                newletter2 = newletter1 + chr(ord(letter) + n)
        newletter1 = newletter2
    return newletter2
def set_dict(fin):
    d = {}
    for line in fin:
        word = line.strip().lower()
        d[word] = 0
    return d
fin = open('words.txt')
count = 0
d = set_dict(fin)
for word in d:    
    for i in range(1, 14): # 8.13.5的习题没有说要移多少位,参考答案直接定义为1-14位,你猜我在想什么
        if rotate_word(word, i) in d:
            print(word, i, rotate_word(word, i))
            count += 1
print(count)
# ......
# zax 1 aby
# zax 4 deb
# zebu 7 glib
# zebu 10 jole
# zee 1 aff
# zee 9 inn
# zips 12 lube
# zoa 6 fug
# zoa 12 lam
# 1137

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